Hallo,
Mach's doch so
Code:
define a Word[1]
define b Word[2]

define c Byte[5]
define d Byte[6]

define e Bit[49]
define f Bit[50]
define g Bit[51]
define h Bit[52]
Word 1 beinhaltet ja schon bit 1-16, word 2 17-32 byte 1 33-40 ...

Matthias